Question

the sum of two number is 80 and the greater number exceeds twice the smaller by 11 find the numbers​

Answer 1

Answer:

Here is ans ...

Step-by-step explanation:

Let us assume, x and y are the two numbers and

x > y

Given:

x +

y = 80 -----------1

Also

given:

x =

2y + 11 --------------2

Substitute

the value of x from equation 1 in equation 2

2y

+ 11 + y = 80

3y

+ 11 = 80

3y

= 69

y =

23

Therefore,

x = 2y + 11 = (2 * 23) + 11 = 57

The

two numbers are 57 and 23 

#Hope it helps ❤

Answer 2

Answer:

Given is that

sum of two numbers is 80

so let the two numbers be x+ÿ=80

now,

second case : that the number x is twice greater and exceeds the smaller number

so equation is

X= 2ÿ+11

now solving both the equation

putting the value of X in

(2y+11)+y=80

3y+11=80

3y=80-11

3y=69

y=69/3

y=23

now you can X=2×23+11=46+11=57