Question

the sum of two number is 80 and the greater number exceeds twice the smaller by 11 find the number in one variabless

Answer 1

Let the two numbers be x (greater number) and y (smaller number)

Then, x=2y+11

Then

x+y=80

2y+11+y=80

3y=69

y=69/3

y=23

Then the numbers are 23
And
2(23)+11
46+11
57

Numbers are 23 and 57.


I hope this much will help you

Answer 2

x+y = 80
y=(80-x)
2x+11=(80-x)
3x=69
x=23

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