The sum of two number is 87. If one exceeds the other by 9, find the number???
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Answered by
0
let two number be x and y
given
x=y+9
also
x+y=87
on keeping value of x in this
y+9+y=87
2y=87-9
2y=78
y=39
x=39+9=48
given
x=y+9
also
x+y=87
on keeping value of x in this
y+9+y=87
2y=87-9
2y=78
y=39
x=39+9=48
Aman091203:
please mark this answer as brainest
Answered by
0
Let the first number be x
then the two numbers are x and (x + 9)
x + (x + 9) = 87
x + x + 9 = 87
2x + 9 = 87
2x = 87 - 9
2x = 78
x = 78 / 2
x = 39
The two numbers are
1. x = 39
2. (x + 9) = 39 + 9 = 48
Hope this helps you
And please don't forget to mark this answer as brainest
then the two numbers are x and (x + 9)
x + (x + 9) = 87
x + x + 9 = 87
2x + 9 = 87
2x = 87 - 9
2x = 78
x = 78 / 2
x = 39
The two numbers are
1. x = 39
2. (x + 9) = 39 + 9 = 48
Hope this helps you
And please don't forget to mark this answer as brainest
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