Question

the sum of two number is 9 if the sum of the squares of those number is 41 then find them​

Answer 1

4&5...................

Answer 2

Answer:

let the first no. be (x)

so the second  no. should be (9-x)

a/q

x2+(9-x)2=41

x2+(81-18x+x2)=41

2x2-18x+81-41=0

2x2-18x+40=0

after factorizing this quadratic eq. we get   x=5,x=4

note: x2 is x square and 2x2 is 2x square.