Question

the sum of two number is 90. One third of the larger number is 9more then twice the smaller one what is the number

Answer 1

Answer:

The required two numbers are 81 and 9.

Step-by-step explanation:

Given :

• the sum of two numbers is 90
• One third of the larger number is 9 more then twice the smaller one

To find :

the numbers

Solution :

Let the larger number be x

and smaller number be y

Sum of the numbers = 90

 x + y = 90 --[1]

One - third of larger number = x/3

Twice the smaller number = 2y

One third of the larger number is 9 more then twice the smaller one

   $\sf \dfrac{x}{3}=9+2y$

x = 3(9 + 2y)

x = 27 + 6y

Substitute x = 27 + 6y in equation [1]

 x + y = 90

27 + 6y + y = 90

27 + 7y = 90

 7y = 90 - 27

 7y = 63

 y = 63/7

 y = 9

The smaller number = 9

The larger number = 27 + 6(9) = 27 + 54 = 81

Therefore, the two numbers are 81 and 9.