Question

The sum of two number is 95. If one number exceeds the other number by 3, find the two numbers​

Answer 1

Answer:

Let other no. be x

then,one no. be x+3

Sum if two no. is 95

A/Q

x+x+3=95

2x=95-3

2x=92

x=92/2

x=46

Thus,other no. will be x=46

one no. will be x+3=46+3

Mark me brain list if my answer is right....

Answer 2

Given :

• sum = 95

$\large \red{ \underline{ \underline{ \green{ \rm \: solution : }}}}$

$\rightarrow$ Let the 1st integer be = x

$\therefore$ 2nd integer = x + 3

$\implies$ x + x + 3 = 95

• On transposing the terms :

$\implies$ x + x = 95 - 3

$\implies$ 2x = 92

$\implies \pink{\rm x = \large \frac{92}{2} }$

$\therefore\rm \:x = 46$

$\bigstar \: \rm \purple{ 1 \: integer = x \: } \blue{ \boxed{\red{= 46}}}$

$\bigstar \purple{ \rm 2 \: integer\: = x + 3 = 46 + 3 = \orange{ \boxed{ \red{ 49}}}}$

• CHECK :

$\rightarrow$x = 46

$\rightarrow$x + 3 = 49

x + x + 3 = 95

$\implies$ 46 + 49 = 95

$\bigstar$ 95 = 95

$\rightarrow$ L.H.S = R.H.S

Hence proved.