Question

The sum of two number is 99 if one exceeds other by 9 find the numbers

Answer 1

Answer:

first number = 45

second number  = 54

Step-by-step explanation:

Let the first number be x and the second number be x+9.

According to the question,

x + x + 9 = 99

=>  2x + 9 = 99

=> 2x = 99 - 9 = 90

=> x = 90 ÷ 2 = 45

first number= x = 45

second number = x+9 =  45 + 9 = 54

Mark this as brainliest, please

Answer 2

Answer:

The no.s are 45 and 54

Step-by-step explanation:

Let the smaller no. be = x

Let the smaller no. be = x Let the bigger no. be = x + 9

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q= x + x + 9 = 99

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q= x + x + 9 = 99= 2x = 99 - 9

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q= x + x + 9 = 99= 2x = 99 - 9 = 2x = 90

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q= x + x + 9 = 99= 2x = 99 - 9 = 2x = 90 = x = 90 ÷2 = 45

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q= x + x + 9 = 99= 2x = 99 - 9 = 2x = 90 = x = 90 ÷2 = 45 Therefore the no.s are

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q= x + x + 9 = 99= 2x = 99 - 9 = 2x = 90 = x = 90 ÷2 = 45 Therefore the no.s are Smaller no. = x = 45

Let the smaller no. be = x Let the bigger no. be = x + 9 So now, A/Q= x + x + 9 = 99= 2x = 99 - 9 = 2x = 90 = x = 90 ÷2 = 45 Therefore the no.s are Smaller no. = x = 45 Bigger no. = x + 9 = 54