Question

the sum of two number is 99 if one exceeds the other by 9 find the numbers​

Answer 1

Let the nos be x and y

x+y=99........equ(1)

Let the no exceeding be x then

x-y =9

x=9+y.........equ(2)

Putting value of x in equ(1)

9+y+y=99

9+2y=99

2y=90

y=45

x=9+y

x=9+45

x=54

Answer 2

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• Other number = 45
• One number = 54

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$\sf{\underline{\green{Given:-}}}$

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• The sum of two number is 99.
• If one exceeds the other by 9.

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$\sf{\underline{\green{Find:-}}}$

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• Other number = ?
• One number = ?

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$\sf{\underline{\green{Explanation:-}}}$

Let the other number be y.

$\:\:\:\:\dag\bf{\underline{\underline \red{Then:-}}}$

• One number = y + 9

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$\sf{\underline\pink{A.T.Q:-}}$

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$\longrightarrow \sf {y + y + 9 = 99}$

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$\longrightarrow \sf {2y + 9 = 99}$

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$\longrightarrow \sf {2y = 99 - 9}$

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$\longrightarrow \sf {2y = 90}$

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$\longrightarrow \sf {y = \cancel\dfrac{90}{2} }$

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$\longrightarrow \sf {y = 45}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• Other number = 45

• One number = 45 + 9

• One number = 54

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$\rule{200}{2}$