Question

the sum of two number is 99. if one exceeds the other by 9, find the number​

Answer 1

Answer:

54 and 45

Step-by-step explanation:

Taking the first no. as x

so the other no. = x+9

equation=

x+x+9=99

2x+9=99

2x=99-9

2x=90

x=90/2

x=45

the other no. = 45+9

=54

verification

45+(45+9)

45+54

99

Answer 2

Answer:

1st number = 45

2nd number = 54

Step-by-step explanation:

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Sum of two number = 99

Let One number be x

Another number = x + 9

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The 1st and 2nd number

$\large{\purple{\fbox{\pink{\bigstar{\mathbf{\green{Solution :-}}}}}}}$

According to the question :

(x) + (x+9) = 99

=> 2x + 9 = 99

=> 2x = 99 - 9

=> 2x = 90

=> x = 90/2

=> x = 45

1st number = x = 45

2nd number = x+9 = 45+9 = 54

$\large{\purple{\fbox{\pink{\bigstar{\mathbf{\green{Verification :-}}}}}}}$

45 + (45+9)

= 45 + 54

= 99

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