The sum of two number is three
and their segnares is 12 then their
preoduct is what?
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Let the numbers be X & Y.
X^2 + Y^2 = 12 —-> 1
X + Y = 3 ——-> 2
Squaring on both sides
(X + Y)^2 = 3^2
X^2 + Y^2 + 2XY = 9
12 + 2XY = 9
2XY = 9 -12
2XY = -3
XY = -3/2 = -1.5 ——> Answer
X^2 + Y^2 = 12 —-> 1
X + Y = 3 ——-> 2
Squaring on both sides
(X + Y)^2 = 3^2
X^2 + Y^2 + 2XY = 9
12 + 2XY = 9
2XY = 9 -12
2XY = -3
XY = -3/2 = -1.5 ——> Answer
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