Question

the sum of two numbers are 19 and the diffrence is 1

Answer 1

Answer:

10,9

Explanation:

Let m,n are two numbers.

according to the problem given,

m+n = 19 ----(1)

m-n = 1 ------(2)

Add (1) and (2) ,we get

2m = 20

=> m = 20/2

=> m = 10

put m = 10 in equation (1) , we get

10+n = 19

=> n = 19-10

=> n = 9

Therefore,

Required two numbers are ,

m =10, n = 9

••••

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Questions}}}}$

Given,

$\textbf{\underline{Sum\;of\;two\;number\;is\;19}}$

$\textbf{\underline{Difference\;is\;1}}$

Assume

Number be v and k respectively

So,

v + k = 19 ....... (1)

v - k = 1 ........... (2)

$\Large{\boxed{\bigstar{{Adding\;both\;Equation :-}}}}$

v + k + (v - k) = 19 + 1

v + k + v - k = 19 + 1

2v = 19 + 1

2v = 20

$\rm \: \: \: \: \: \: \: \: \:v=\dfrac{\cancel{20}}{\cancel{2}}$

v = 10

Hence,

$\Large{\boxed{\bigstar{{First\;number= 10}}}}$

$\Large{\boxed{\bigstar{{Second\;number:-}}}}$

v + k = 19

10 + k = 19

k = 19 - 10

k = 9

Therefore,

$\huge{\boxed{\sf\:{First\;number = 10\;and\;Second\;number = 9}}}$