the sum of two numbers ,as well as, the differ between their square is 9
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Answered by
1
Hi friend, Here is the required answer:-
If you just think of the numbers 4&5, you can calculate that their sum is 9. So, there is a chance that the numbers could be the answer. Now calculate the difference between their squares. That is 5²-4²=25-16=9.
So the required numbers are 4&5.
Hope this helps you...
Please mark as brainliest answer!!!
If you just think of the numbers 4&5, you can calculate that their sum is 9. So, there is a chance that the numbers could be the answer. Now calculate the difference between their squares. That is 5²-4²=25-16=9.
So the required numbers are 4&5.
Hope this helps you...
Please mark as brainliest answer!!!
Answered by
4
Let the numbers be 'x' and 'y'.
According to the problem,
x+y=9--------(1)
x²-y²=9----(2)
⇒(x+y)(x-y)=9
⇒9(x-y)=9
⇒(x-y)=9/9
⇒(x-y)=1-----(3)
Eq(1)+eq(3)⇒2x=10
x=5
Substituting x=5 in (1)⇒5+y=9
y=9-5
y=4
Therefore,the numbers are 5 and 4.
According to the problem,
x+y=9--------(1)
x²-y²=9----(2)
⇒(x+y)(x-y)=9
⇒9(x-y)=9
⇒(x-y)=9/9
⇒(x-y)=1-----(3)
Eq(1)+eq(3)⇒2x=10
x=5
Substituting x=5 in (1)⇒5+y=9
y=9-5
y=4
Therefore,the numbers are 5 and 4.
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