Question

the sum of two numbers exceeds thrice the smaller by 2 if the difference between them is 19 find the number​

Answer 1

Answer:

x = 36

y = 17

Step-by-step explanation:

Let one number be x.

Then the other number will be y.

(Assuming y the smaller number)

x + y > 3y { x + y is greater than 3y by 2)

Hence,

x + y - 2 = 3y

x - 2y = 2 ----------1

Now,

x - y = 19 -----------2

Subtracting 1 and 2

x - 2y = 2

-(x) - (-y) = -(19)

=> -y = -17

=> y = 17

Therefore

x = 19 + y ------------by 2 equation

x = 19 + 17

x = 36

Hence Answer given above.

Answer 2

Step-by-step explanation:

Let the numbers be X and Y Taking X>Y Therefore from the given data we can gather that

(1) X + Y = 3Y + 2 (2) X - Y = 19

From the second equation we can say that:

X = 19 + Y Substitute this value of X in equation 1 to get

19 + 2Y = 3Y + 2 Rearrange the equation Y = 17

X = Y + 19

X = 17 + 19

X = 36

hope it helps please mark as brainliest........