The sum of two numbers exceeds thrice the smaller by 2. If the difference between them is 19,find the numbers. Please answer quickly. It's urgent
Answers
Answered by
0
Step-by-step explanation:
let A greater no. B smaller no.
A+B=3B+2. eq1
A-B=19. eq2
from eq 2
A= 19 + B
value of A in eq 1
(19 + B)+B = 3B+2
19+2B= 3B+2
3B-2B = 19-2
B= 17
A= 17+19
A = 36
therefore, A= 36, B = 17
Answered by
0
Step-by-step explanation:
understand pic it is by substituting values of x and y.
Attachments:
Similar questions