The sum of two numbers is 1,600.
If 12% of one is equal to 20% of the other, then find the numbers,
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let 1st no is x so 2nd will be 1600-x
a.t.q.
12% of 1st=20% of 2nd
0.12x= 0.20(1600-x)
0.12x= 320-0.20x
0.32x= 320
x= 320 / 0.32
x= (320 * 100) / 32
x=1000 --Ans
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