Question

The sum of two numbers is 1,600.if 12% of one is equal to 20% of the other,then find the numbers.

Answer 1

Answer:

The numbers are 1000 and 600.

Explanations:

Let the first number be x and the second number be y.

Given : The sum of two numbers is 1600.

i.e. x+y=1600x+y=1600 (1)

12% of one number = 0.012x

20% of the other number = 0.20y

If 12% of one is equal to 20% of the other

\begin{gathered}\Rightarrow\ 0.12x=0.20y\\\\\Rightarrow\ y=\dfrac{0.12x}{0.20}=0.6x\end{gathered}

⇒ 0.12x=0.20y

⇒ y=

0.20

0.12x

=0.6x

Put y=0.6x in (1) , we get

x+0.6x=1600x+0.6x=1600

x(1.6)=1600x(1.6)=1600

x=\dfrac{1600}{1.6}=1000x=

1.6

1600

=1000

From (1) , y= 600

Hence, the numbers are 1000 and 60

Step-by-step explanation:

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