Question

The sum of two numbers is 10. Show that the sum of their squares cannot be less than 50​

Answer 1

Answer:

let 1 st no. be x.

so,2nd no.=10-x. ( because2nd no.+x=10)

now x²+(10-x)²=x²+100-20x+x²

=2x²-20x+100

=x²-10x+50

x=0 or x=10

so 1st no. be 0 and 2nd no.=10

so (0)²+(10)²=100>50

from this we get that their squares cannot be less than 50.

hope it will help you.