The sum of two numbers is 10. Three times the smaller exceeds the larger by 2. The smaller number is
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3x÷2+x=10
4x÷2=10
4x=10÷2
4x=5
x=5/4
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Answer:
The smaller number is a = 3 and b = 7.
Step-by-step explanation:
Given:
The sum of two numbers exists 10. Three times the smaller exceeds the larger by 2.
To find:
The smaller number is
Step 1
From the given information, we get
a + b = 10 ......(1)
3a = b + 2
3a - b = 2 ......(2)
On adding equation (1) and (2) we get
4a = 12
a =12/4
a = 3
Step 2
On equating, we get a = 3
From equation (1) we get
a + b = 10
3 + b = 10
then b = 10 - 3
b = 7
Therefore, the given smaller number is a = 3 and b = 7.
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