The sum of two numbers is 1000 and the difference between their squares is 256000 find the numbers
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let the two numbers be x and y respectively
according ti 1st condition,
x+y=1000--------------------(1)
according to 2nd condition
x^2-y^2=256000
=>(x+y)(x-y)=256000
=>1000(x-y)=256000
=>x-y=256--------------------(2)
add equation (1) and (2),we get
2x=1256
x=628
put x=628 in equation (1) we get
628+y=1000
y=1000-628
y=372
according ti 1st condition,
x+y=1000--------------------(1)
according to 2nd condition
x^2-y^2=256000
=>(x+y)(x-y)=256000
=>1000(x-y)=256000
=>x-y=256--------------------(2)
add equation (1) and (2),we get
2x=1256
x=628
put x=628 in equation (1) we get
628+y=1000
y=1000-628
y=372
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