The sum of two numbers is 1000 and the difference between their squares is 256000. Find the numbers
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Answers
Answered by
2
Let the two numbers be x and y respectively
x+y=1000
x=1000-y
x^2-y^2=256000
(1000-y)^2-y^2=256000
1000000-2000y+y^2-y^2=256000
-2000y=256000-1000000
-2000y=-744000
2000y=744000
y=744000/2000
y=372
x=1000-372
x=628
Therefore, the two numbers are 628 and 372 respectively
x+y=1000
x=1000-y
x^2-y^2=256000
(1000-y)^2-y^2=256000
1000000-2000y+y^2-y^2=256000
-2000y=256000-1000000
-2000y=-744000
2000y=744000
y=744000/2000
y=372
x=1000-372
x=628
Therefore, the two numbers are 628 and 372 respectively
Answered by
3
x+y=1000
x2-y2=256000
but x2-y2=(x+y)(x-y)
256000=1000(x-y)
x-y=256
x=256+y
now x+y=1000
256+y+y=1000
2y=1000-256=744
y=372
x+y=1000
x=1000-372
x=628
x2-y2=256000
but x2-y2=(x+y)(x-y)
256000=1000(x-y)
x-y=256
x=256+y
now x+y=1000
256+y+y=1000
2y=1000-256=744
y=372
x+y=1000
x=1000-372
x=628
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