The sum of two numbers is 104 and their difference is 30. What is the difference
between their squares?
Answers
Answered by
0
Answer:
3120
Step-by-step explanation:
STEP 1 :
Let the numbers be x and y.
x + y= 104 ... (i)
x - y = 30 ....(ii)
solving eqns (i) and (ii)
2x = 134
x= 67 and y = 37
x² - y²
using identity a²-b² = (a+b)(a-b)
(67+37)(67-37)
=104 × 30
=3120
STEP 2 :
we know that, a²-b² = (a+b)(a-b)
∴ d= 104 × 30
= 3120
where d is the difference between their squares.
Answered by
1
Answer:
3120
Step-by-step explanation:
let one number be "a" and other number be "b"
given
a+b =104
a-b =30
to find
a^2 -b^2
solution
a^2- b^2 = (a+b)(a-b)
= (104)(30)
= 3120
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