The sum of two numbers is 11 and twice their product is 48 .find the numbers
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Step-by-step explanation:
a+b=11⟹a=11−b
2ab=48
⟹2b(11−b)=48
⟹2b2−22b−48=0
⟹b2−11b−24=0
⟹(b−3)(b−8)=0
b=3 or 8
a=8 or 3
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