Question

The sum of two numbers is 128.
and there diffrence is 114​

Answer 1

Answer:

Let X = smaller number; Y = larger number

Translate:

"sum of two numbers is 128" means

X + Y = 128 (eq1)

"three times the smaller number is subtracted from the larger number the result is 12"

means Y - 3X = 12 (eq2)

Solve using elimination method:

X + Y = 128 (eq1)

-3X + Y = 12 (rearrange eq2)

--------------------------- (elimination method; subtract equations)

4X = 116

x = 29 (divide both sides by 4) (eq3)

x + y = 128 (eq1 again)

-------------------------- (carefully subtract eq3 from eq1)

y = 99

Checking (very important):

Is 29 + 99 = 128 ?

128 = 128 ? yes

Is 99 - 3*29 = 12 ?

99 - 87 = 12 ?

12 = 12 ? yes

Answer 2

Answer:

solve this

x + Y = 128

and x-y = 114

then by adding both expressions we get

128 -y = 114 + y

hence 14 = 2y

y = 7 ans

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