The sum of two numbers is 15 and sum of their resiprocals is 3/10 the number ate
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Sol: Let one of the numbers be x. Other number is (15 - x) Sum of their reciprocals = 3/10 1/x + 1/(15 - x) = 3/10 (15 ) / (15x - x2) = 3/10 150 = 45x - 3x2 3x2 - 45x + 150 = 0 x2 - 15x + 50 = 0 (x - 10)(x - 5) = 0 x = 10 or 5 Therefore, the numbers are 10 and 5. If x = 15
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let me tell you the solution now
Sol: Let one of the numbers be x. Other number is (15 - x) Sum of their reciprocals = 3/10 1/x + 1/(15 - x) = 3/10 (15 ) / (15x - x2) = 3/10 150 = 45x - 3x2 3x2 - 45x + 150 = 0 x2 - 15x + 50 = 0 (x - 10)(x - 5) = 0 x = 10 or 5 Therefore, the numbers are 10 and 5. If x = 15
I hope it will help you ✨✨✨✨
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