Question

the sum of two numbers is -15 and their product is 56 .find the number s​

Answer 1

Answer:

-7 and -8

plz mark me as a BRAINLIEST

Answer 2

ANSWER:

Given:

• Sum of 2 numbers is -15
• Product of the numbers 56.

To Find:

• The numbers.

Solution:

Let one number be x.

As the sum of 'x' and other number is -15,

So, the other number is (-15 - x).

We are also given that,

⇒ x * (-15 - x) = 56

So,

⇒ x * (-15 - x) = 56

⇒ -15x - x² = 56

Transposing LHS to RHS,

⇒ 0 = 56 + 15x + x²

⇒ x² + 15x + 56 = 0

Splitting the middle term,

⇒ x² + 7x + 8x + 56 = 0

⇒ x(x + 7) + 8(x + 7) = 0

⇒ (x + 7)(x + 8) = 0

⇒ x = -7 or -8

So,

⇒ (-15 - x)

⇒ (-15 - (-7)) or (-15 -(-8))

⇒ (-15 + 7) or (-15 + 8)

⇒ -8 or -7.

So,

The numbers are -7 and -8 respectively.

Verification:

We know that,

⇒ Sum of numbers = -15.

⇒ -7 + (-8)

⇒ -15. = RHS ----(1)

We know that,

⇒ product of numbers = 56.

⇒ (-7) * (-8)

⇒ 56 = RHS ----(2)

From (1) & (2),

Hence Verified!!!