The sum of two numbers is 15. If sum of their resipocals is 3/10 find the two numbers
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Answer:
x+y=15
1/x+1/y=3/10
then
10(x+y)=3xy
150=3xy
xy=50
(15-y)*y=50
y^2-15y+50=0
y^2-10y-5y+50=0
y(y-10)-5(y-10)=0
(y-5)(y-10)=0
y=5 or 10
if y=5
then
x=15-5=10
so the numbers are
10 and 5
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