The sum of two numbers is 156 and their HCF is 13. The numbers
of such number pairs is
WHOEVER ANSWERS THIS CORRECT
I WILL MARK THE BRAINLIEST ^_^
Answers
The required pairs are: i) 13 and 143 or ii) 65 and 91
Step-by-step explanation:
Consider the provided information.
HCF of the two numbers are 13.
Lets say two numbers are: 13A and 13B
Where A and B are co-prime numbers
Therefore, HCF of A and B = 1
The sum of two numbers is 156
13A + 13B = 156
13(A + B) = 156
A + B = 12
Thus, the possible case are:
1 + 11 = 12
2 + 10 = 12 (2 and 10 are not co-prime)
3 + 9 = 12 (3 and 9 are not co-prime)
4 + 8 = 12 (4 and 8 are not co-prime)
5 + 7 = 12
6 + 6 = 12 (6 and 6 are not co-prime)
For A=1 and B=11
13×1=13 and 13×11=143
For A=5 and B=7
13×5=65 and 13×7=91
Hence, the required pairs are: i) 13 and 143 or ii) 65 and 91
MARK AS BRAINLIEST
Answer:
The required pairs are: i) 13 and 143 or ii) 65 and 9
Step-by-step explanation:
Consider the provided information.
HCF of the two numbers are 13.
Lets say two numbers are: 13A and 13B
Where A and B are co-prime numbers
Therefore, HCF of A and B = 1
The sum of two numbers is 156
13A + 13B = 156
13(A + B) = 156
A + B = 12
Thus, the possible case are:
1 + 11 = 12
2 + 10 = 12 (2 and 10 are not co-prime)
3 + 9 = 12 (3 and 9 are not co-prime)
4 + 8 = 12 (4 and 8 are not co-prime)
5 + 7 = 12
6 + 6 = 12 (6 and 6 are not co-prime)
For A=1 and B=11
13×1=13 and 13×11=143
For A=5 and B=7
13×5=65 and 13×7=91
Hence, the required pairs are: i) 13 and 143 or ii) 65 and 91