Question

The sum of two numbers is 156 and their HCF is 13,the number of such number of pairs is ?

Answer 1

Answer:

Step-by-step explanation:

Its 13 and 143

Answer 2

Step-by-step explanation:

there are two numbers having HCF = 13

Then Lets say two numbers are

13A & 13B

where A & B are co-prime numbers

so that HCF of A & B = 1

Sum of two numbers = 156

$⇒ 13A + 13B = 156$

$⇒13(A + B) = 156$

⇒ a + b = 12[/tex]

$⇒1 + 11 = 12$

2 + 10 = 12 (but 2 & 10 are not co -prime, 2 is their HCF)

3 + 9 = 12 (but 3 & 9 are not co-prime, 3 is their HCF)

4 + 8 = 15 (but 4 & 8 are not co-prime, 4 is their HCF)

$5 + 7 = 1$

6 + 6 12 ( 6 is their HCF)

13 & 143

65 & 91

so two such pairs.