Question

The sum of two numbers is 16 and eight times of their difference is equal to their sum. Find the numbers​

Answer 1

Step-by-step explanation:

x+y = 16

8(x-y) = x+y

8(x-y) = 16

x-y = 2

from these two equations we get:

x = 9

y = 7

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Answer 2

Solution:

Let first no. = x
Let another no. = y

Therefore, x+y=18 (given in the question). —— (1)
When, eight times their difference is equal to the sum,

8(x-y)= x+y

8x-8y= x+y

7x-9y=0 —— (2)

If, we multiply 7 with (1) then,

7x+7y =126 —— (A)

Now, (A)-(2)

So, 7y+9y =126
16y = 126
y= 126/16
y= 63/8

7x- 9*63/8 =0 ( * sign of multiplication)
7x- 567/8 =0
x= 567/8*7
x= 81/8

Hence, the value of x is 81/8 and y is 63/8.



Check:
x+y =0
81/8+ 63/8= 144/8
x+y= 18 (Divide 144 by 8)

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