Question

The sum of two numbers is 16 and sum of their reciprocal is 1/3. Find the numbers.​

Answer 1

Answer:

Y=4,Y=12

Step-by-step explanation:

let X and Y be the two given no then

X+Y=16

1/X+1/Y=1/3

X+Y/xy=1/3

16/xy=1/3

xy=16*3=48

X=48/Y

now put this into first equation

you get 48/Y+Y=16

48+y2=16y

y2-16y+48=0

y2-12y-4y+48=0

Y(y-12)-4(y-12)=0

(y-4)(y-12)=0

Y=12

or Y=4