the sum of two numbers is 16 and the sum of their reciprocals is 16/63 find the numbers
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Answered by
6
Answer:
7 and 9
Step-by-step explanation:
Numbers=x, y
x+y=16
1/x+1/y=16/63
(x+y)/XY =16/63
we know x+y=16
ie, 16/xy=16/63
XY=63
x=63/y
ie.x+y=63/y+y
=( 63+y²)/y=16
=63+y²-16y
Y² - 9y - 7y + 63 =0 [spliting method ]
y(y-9) -7(y-9 ) =0
(y-9)(y-7) = 0
y-9 = 0
y = 9
ie x=63/9=8
and next value of y is
y - 7 =0
y = 7
ie x=63/7=9
numbers= 7 and 9
Answered by
4
Step-by-step explanation:
its yur solution dear.....
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