Question

The sum of two numbers is 16 and their diference is 12

Answer 1

Answer:

The sum of two numbers is 16 and their difference is 12. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 16. In other words, x plus y equals 16 and can be written as equation A:

x + y = 16

The difference between x and y is 12. In other words, x minus y equals 12 and can be written as equation B:

x - y = 12

Now solve equation B for x to get the revised equation B:

x - y = 12

x = 12 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 16

12 + y + y = 16

12 + 2y = 16

2y = 4

y = 2

Now we know y is 2. Which means that we can substitute y for 2 in equation A and solve for x:

x + y = 16

x + 2 = 16

X = 14

Summary: The sum of two numbers is 16 and their difference is 12. What are the two numbers? Answer: 14 and 2 as proven here:

Sum: 14 + 2 = 16

Difference: 14 - 2 = 12

Answer 2

Answer:

The numbers are $14$ and $2$.

Step-by-step explanation:

Let the first number be $x$

Second number be $y$

According to question,

$x+y=16$  ---(1)

$x-y=12$ ----(2)

Adding both equations,

$2x=28$

$x=14$

Putting it in (2)

$y=14-12=2$

Hence, numbers are $14$ and $2$

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