the sum of two numbers is 16 and their product is 63
Answers
Answer:
The numbers are 7 and 9
Step-by-step explanation:
let the numbers be x and y.
now, x + y = 16 ................. (i)
and xy = 63 ...................... (ii)
now, y= 16 - x ......................(iii)
substitute eq (iii) in eq (ii)
x(16 - x) = 63
16x - x² = 63
x² - 16x + 63 = 0
x² - 7x -9x + 63 = 0
x(x-7) -9(x-7)
(x-9)(x-7) = 0
x= 9 or x = 7
if x= 9,
then 9×y= 63
y=7
if x= 7
7×y= 63
y=7
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Let numbers are x and y
x+y=16........(1)
xy=63
x=63y.........(2)
Put the value of x in (1)
63/y+y=16
Multiply by y both sides
63+y^2=16y
Rearrage above equation
y^2-16y+63=0
y^2-9y-7y+63=0
y(y-9)-7(y-9)=0
(y-7)(y-9)=0
y-7=0 or y-9=o
y=7 or y=9
Put the values of y in (1)
x=7
x+y=16
x+7=16
x=16-7
x=9
x+9=16
x=16-9
x=7
if one number is 7 other will be 9 or one is 9 other will be 7.
So numbers are 7 and 9