Question

The sum of two numbers is 1600. If 12% of one is equal to 20% of the other, then find the numbers

Answer 1

Step-by-step explanation:

LET THE FIRST NUMBER BE 'X'

THEN THE SECOND NUMBER BE =1600-x

According to the condition in the QUESTION we get...

12% of x = 20% ( 1600 - x)

12/100 * - 12/100 * (1600 - x)

12x= 32000 -20x

32x= 32000

x=32000/32

SO...

X=1000

FIRST NUMBER = X = 1000 and SECOND NUMBER = 1600 - x-1600-1000 = 600

SO UA ANSWER WILL BE........600

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#ANSWER WITH QUALITY....