Question

The sum of two numbers is 18. If one exceeds the other by 6, find the larger number​

Answer 1

Answer:

The answer is 12.

Step-by-step explanation:

The explanation is in the attachment.

Answer 2

Question:

The sum of two numbers is 18. If one exceeds the other by 6, find the larger number.

To find:

• Larger number

Given :

• Sum of two numbers = 18
• One number exceeds other by 6

Let:

• First number = x
• Second number = x+ 6

Solution:

We know:

$\checkmark\boxed{ \rm{}First \: number + Second \: number = 18}$

$: \implies \sf{}x +x + 6 = 18$

$: \implies \sf{}2x+ 6 = 18$

$: \implies \sf{}2x= 18 - 6$

$: \implies \sf{}2x= 12$

$: \implies \sf{}x= \dfrac{12}{2}$

$: \implies \sf{}x= \cancel \dfrac{12}{2}$

$: \implies \underline{ \boxed{\sf{}x=6}}$

Now before finding numbers Let's Verify value of x

$: \implies \sf{}x +x + 6 = 18$

put value of x in this equation

$: \implies \sf{}6 +6 + 6 = 18$

$: \implies \sf{}3 \times 6= 18$

$: \implies \underline{ \boxed{\sf{}18= 18}}$

LHS=RHS

Hence verified!

Now Let's find value of numbers

• First number =x
• First number = 6

• Second number = x+ 6
• Second number =6 +6
• Second number = 12

.°. Value of larger number= $\underline {\boxed{\bf{12}}}$