the sum of two numbers is 18 .The sum of their reciprocals is 1/4.Find the numbers.
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here is your answer .
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Anonymous:
oops our ans are totally different
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Heya
______________________________
let the numbers be x and y
ACCORDING TO THE QUESTION
x + y = 18.... Equation ( i )
1/x + 1/y = 1/4
=>
x + y = xy/4
=>
18 = xy/4
=>
xy = 72 .... Equation ( ii )
y = 72 / x
Put value of y in Equation ( i )
72/x + x = 18
=>
x² -18x + 72 = 0
=>
x = (18 + 6 )/ 2
OR
x = ( 18 - 6 ) /2
=>
x = 12
OR
x = 6
For x = 12 y = 6
For x = 6 y = 12
______________________________
let the numbers be x and y
ACCORDING TO THE QUESTION
x + y = 18.... Equation ( i )
1/x + 1/y = 1/4
=>
x + y = xy/4
=>
18 = xy/4
=>
xy = 72 .... Equation ( ii )
y = 72 / x
Put value of y in Equation ( i )
72/x + x = 18
=>
x² -18x + 72 = 0
=>
x = (18 + 6 )/ 2
OR
x = ( 18 - 6 ) /2
=>
x = 12
OR
x = 6
For x = 12 y = 6
For x = 6 y = 12
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