Question

The sum of two numbers is 184. 1/3rd of one number exceeds 1/7th of the other number by 8. Find two numbers?​

Answer 1

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• Suppose both numbers are x and y
• x+y = 184___(1)
• Also,
• $\frac{x}{3} = \frac{y}{7} + 8$
• $= \frac{7x}{3} = y + 56$
• $7x = 3y + 168 \\ 7x - 3y = 168(2)$
• Multiply (1) by 3 and subtract
• $3x + 3y = 552 \\ - (7x - 3y = 168)$
• We get -3x=-730
• $x = \frac{730}{3}$

Answer 2

Step-by-step explanation:

hope the above answer will help you