Question

the sum of two numbers is 184 .one-third of one number exceeds One-seventh of the other number by 8 .find the two numbers​

Answer 1

Answer :

• The two numbers are 72 and 112

Given :

• The sum of two numbers is 184
• One - third of one number exceeds one - seventh of the other number by 8

To find :

• The two numbers

Solution :

Given that,

The sum of two numbers is 184 so ,

• Let the first number be x
• Let the second number be 184 - x

Now ,

⇢ x/3 - (184 - x)/7 = 8

⇢[ 7x - 3 (184 - x)]/21 = 8

⇢ 7x - 552 + 3x = 21 × 8

⇢ 10x = 168 + 552

⇢ 10x = 720

⇢ x = 720/10

⇢ x = 72

Hence ,

• One number is 72
• Second number is 184 - x = 184 - 72 = 112

Hence , The two numbers are 72 and 112

Answer 2

Answer:

Answer :

The two numbers are 72 and 112

Given :

The sum of two numbers is 184

One - third of one number exceeds one - seventh of the other number by 8

To find :

The two numbers

Solution :

Given that,

The sum of two numbers is 184 so ,

Let the first number be x

Let the second number be 184 - x

Now ,

⇢ x/3 - (184 - x)/7 = 8

⇢[ 7x - 3 (184 - x)]/21 = 8

⇢ 7x - 552 + 3x = 21 × 8

⇢ 10x = 168 + 552

⇢ 10x = 720

⇢ x = 720/10

⇢ x = 72

Hence ,

One number is 72

Second number is 184 - x = 184 - 72 = 112

Hence , The two numbers are 72 and 112

Step-by-step explanation:

Hope this answer will help you.✌️