Question

the sum of two numbers is -2/3 . if one of the no. is 6/11 .find the another no

Answer 1

Hope it helps you ✔️ ✅✔️

Answer 2

$\Large{\underline{\underline{\mathfrak{\green{\bf{Question}}}}}}$

the sum of two numbers is -2/3 . if one of the no. is 6/11 .find the another no

$\Large{\underline{\underline{\mathfrak{\green{\bf{Solution}}}}}}$

$\Large{\underline{\underline{\mathfrak{\pink{\bf{Given}}}}}}$

• the sum of two numbers is -2/3
• one of the no. is 6/11

$\Large{\underline{\underline{\mathfrak{\pink{\bf{Find}}}}}}$

• Other Number ?

$\Large{\underline{\underline{\mathfrak{\orange{\bf{Explanation}}}}}}$

Let, second number is a ,

So, A/c to question

$\mapsto\sf{\:\dfrac{6}{11}\:+\: a\:=\:\dfrac{-2}{3}}$

$\mapsto\sf{\:a\:=\:\dfrac{-2}{3}\:-\:\dfrac{6}{11}}$

$\mapsto\sf{\:a\:=\:\dfrac{-2\times 11\:-\:6\times 3}{33}}$

$\mapsto\sf{\:a\:=\:\dfrac{-22-18}{33}}$

$\mapsto\sf{\green{\:a\:=\:\dfrac{-40}{33}\:\:\:\:\:Ans}}$

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$\Large{\underline{\underline{\mathfrak{\orange{\bf{\:Answer\:Verification}}}}}}$

A/c to question,

$\:\:\:\:\:\:\small\textsf{\green{ (the sum of two numbers is -2/3 )}}$

$\mapsto\sf{\:\dfrac{6}{11}\:+\:\dfrac{-40}{33}\:=\:\dfrac{-2}{3}}$

$\mapsto\sf{\:\dfrac{6\times 3-\:40}{33}\:=\:\dfrac{-2}{3}}$

$\mapsto\sf{\:\dfrac{18-40}{33}\:=\:\dfrac{-2}{3}}$

$\mapsto\sf{\:\dfrac{-\cancel{22}}{\cancel{33}}\:=\:\dfrac{-2}{3}}$

$\mapsto\sf{\pink{\:\dfrac{-2}{3}\:=\:\dfrac{-2}{3}}}$

$\Large{\sf{\bf{\:L.H.S.\:=\:R.H.S.}}}$

That's proved

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