Question

the sum of two numbers is 216 and their HCF is 27 the numbers are

Answer 1

howdy!!


your answer is -----

let the two no. be x and y respectively.
then, 
        x+y=216
 
since, 27 is their HCF

so each number must be divisible by 27.

so let x=27a and y= 27b ;

now, 27a + 27b=216
          
=> a + b =216/27
         
  => a + b= 8
           so possible values for (a,b) are (5,3), (6,2) and (7,1) order can be reverse it is highly unlikely order could (4,4)
So no. could be (135,81) and so on



hope it help you
=============✌✌✌✌✌✌✌☺☺☺☺☺

Answer 2

Given,
Sum of numbers = 216
HCF = 27
Since HCF is the common factor of both numbers:
27*(a+b) = 216
a+b = 216/27 = 8
Hence possible combinations (a,b): (1,7), (3,5)
Numbers can be: (27,189) or (81,135)