Question

The sum of two numbers is 24 and the sum of their squares is 288. Find the numbers. ces: (b) 12.5 (d) 13 (a) 25 (c) 12​

Answer 1

Answer:

6 and 18

Step-by-step explanation:

let one number be x

therefore the other number is 24-x

ATP,

x^2 + (24-x)^2=288

=>x^2 + (576 -48x -x^2)=288

=>x^2 + 576 - 48x -x^2 =288

=>576 - 48x=288

=>576-288=48x

=>288=48x

=>x=288/48

=>x=6

I think the question is incorrect