Question

The sum of two numbers is 24. One number is 2 times as large as the other. What are the numbers?

Answer 1

Answer :-

• The numbers are 8 and 16.

Given :-

• The sum of two numbers is 24.
• One number is two times as large as the other.

To find :-

• The numbers.

Step-by-step explanation :-

• Let the other number be "x".

• As one of the numbers is two times as large as the other, it will be 2x.

• Now, their sum is 24.

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Hence,

$\longmapsto\sf x + 2x = 24$

Adding 2x to x,

$\longmapsto\sf3x = 24$

Transposing 3 from LHS to RHS, changing it's sign,

$\longmapsto\sf x = \dfrac{24}{3}$

Dividing 24 by 3,

$\longmapsto\overline{\boxed{\sf x = 8}}$

• The value of x is 8.

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Hence, the numbers are as follows :-

$\bf x = 8.$

$\bf2x = 2 \times 8 = 16.$

Answer 2

Given :

• The Sum of two numbers is 24.
• One number is 2 times as large as the other.

To Find :

• The Numbers

Solution :

✰ In this question, it is given that sum of two numbers is 24 and one number is 2 times as large as the other. So for finding the numbers we will assume the first number be p and second number be 2p as second number is 2 times the first number. Now According to the Question, Sim of the two numbers = 24 (p + 2p = 24) so we will simply solve this equation to find the numbers.

⠀⠀

⠀⠀⟼⠀⠀p + 2p = 24

⠀⠀⟼⠀⠀3p = 24

⠀⠀⟼⠀⠀p = 24/3

⠀⠀⟼⠀⠀p = 8

⠀

Therefore :

➥ First Number = p

➥ First Number = 8

⠀

➥ Second Number = 2p

➥ Second Number = 2 × 8

➥ Second Number = 16

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