Question

the sum of two numbers is 24 .one number is twice the other number .find the other number​

Answer 1

• One number = 16.
• The other number = 8.

Given :

• The sum of two numbers = 24.
• One number is twice the other number.

To Find :

• The other number.

Solution :

Let,

The other number be x.

The one number be 2x because according to the question, one number is twice the other number.

According to the condition,

Sum of the both numbers is 24.

$\boxed{ \pink {\sf{one \: number + other \: number = 24}}}$

First, we need to find the value of x.

$\implies \rm2x + x = 24 \\ \\ \implies \rm3x = 24 \\ \\ \implies \rm x = \dfrac{24}{3} \\ \\ \implies \rm x = 8$

So,

The numbers are :

★ One number = 2x = 2 × 8 = 16.

★ Other number = x = 8.

Hence,

The two numbers are 16 and 8.

Verification :

$\boxed{ \pink {\sf{one \: number + other \: number = 24}}}$

Now we have,

• One number = 16.
• Other number = 8.

$\implies \rm16 + 8 = 24 \\ \\ \implies \rm24 = 24$

Hence Verified !