The sum of two numbers is 25. If the first number is decreased by 5 the second is increased by 1. the product of the new no. s is 108 find the original numbers.
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Answer:
let x be first number and y be second number.
by given condition,
x+y=25
.•.x=25-y------------------[1]
by second condition,
(x-5)(y+1)=108
(25-y-5)(y+1)=108------------------[from 1]
(20-y)(y+1)=108
20y+ 20 -y^2 -y=108
-y^2+19y+20-108=0
y^2-19y+88=0-----------[multiplying by -1]
y^2-11y-8y+88=0
y(y-11)-8(y-11)=0
(y-8)(y-11)=0
y-8=0. or. y-11=0
y=8. or. y=11
put y=8 in [1],
x=25-8
x=17
put y=11 in [1]
x=25-11
x=14
.•.x=17. and. y=8
or
.•.x=14. and. y=11
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