Question

The sum of two numbers is 256. If 32 is their H.C.F. and each of the two numbers is greater than 50, what s their L.C.M.?​

Answer 1

Answer:

Let the two numbers be x and y respectively.

It is given that the sum of the two numbers is 684, therefore,

x+y=684

Also 57 is their HCF, thus both numbers must be divisible by 57.

So, let x=57a and y=57b, then

57a+57b=684

⇒57(a+b)=684

⇒a+b=

57

684

⇒a+b=12

Therefore, required possible pair of values of x and y which are prime to each other are (1,11) and (5,7).

Thus, the required numbers are (57,627) and (285,399).

Answer 2

Answer:

96 and 160

Step-by-step explanation:

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