the sum of two numbers is 29 and the difference of their squares is 145. the difference between the number is
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Hey!!!
Here is your answer__________
let a and b the two numbers.
from given first condition,
(a + b) = 29 -------------(1)
by given second condition,
(a^2) - (b^) = 145 ----------(2)
we know that,
x^2 - y^2 = (x + y)( x - y)
hence equation (2) can be written as,
(a + b)(a - b) = 145
from equation (1) we get,
29(a - b) = 145
(a - b) = 145/29
(a - b) = 5
therefore the difference between the numbers is 5.
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Hope this answer will help u....
Here is your answer__________
let a and b the two numbers.
from given first condition,
(a + b) = 29 -------------(1)
by given second condition,
(a^2) - (b^) = 145 ----------(2)
we know that,
x^2 - y^2 = (x + y)( x - y)
hence equation (2) can be written as,
(a + b)(a - b) = 145
from equation (1) we get,
29(a - b) = 145
(a - b) = 145/29
(a - b) = 5
therefore the difference between the numbers is 5.
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Hope this answer will help u....
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