Question

The sum of two numbers is 3000. If 8% of one number is equal to 12% of the other, find the numbers.

Answer 1

Heya user !!!

Here's the answer you are looking for

Let the two numbers be x and y.

Given, x + y = 3000

Also,
$\frac{8x}{100} = \frac{12y}{100} \\ 8x = 12y \\ 2x = 3y \\ x = \frac{3}{2} y$


We got x = 3y/2

But x + y = 3000

3y/2 + y = 3000

5y/2 = 3000

y = 3000 × 2 / 5 = 1200

So, x = 3(1200)/2 = 1800


Therefore, the two numbers are 1800 and 1200.


★★ HOPE THAT HELPS ☺️ ★★

Answer 2

Answer:

1800and 1200

Step-by-step explanation:

Let 1st number be x

2nd number is 3000-x

According to the question.

8x/100=(3000-x)12/100

8x/100=(36000-12x/100

8x+12x=36000

20x=36000

x=1800

hence the 1st number is 1800

2nd number is 3000-1800=1200