The sum of two numbers is 3000. If 8% of one number is equal to 12% of the other, find the numbers.
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Two numbers are 1800 and 1200
Anuradha111111:
show me the process
Let the two numbers be x and y.
Given, x + y = 3000
Also,
We got x = 3y/2
But x + y = 3000
3y/2 + y = 3000
5y/2 = 3000
y = 3000 × 2 / 5 = 1200
So, x = 3(1200)/2 = 1800
Therefore, the two numbers are 1800 and 1200.
Given, x + y = 3000
Also,
We got x = 3y/2
But x + y = 3000
3y/2 + y = 3000
5y/2 = 3000
y = 3000 × 2 / 5 = 1200
So, x = 3(1200)/2 = 1800
Therefore, the two numbers are 1800 and 1200.
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