Question

The sum of two numbers is 3000. If 8% of one number is equal to 12 % of the other, find the numbers.​

Answer 1

Answer:

I don't know

Step-by-step explanation:

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Answer 2

Answer:

The numbers are 1200 and 1800

Explanation:

Given that,

Sun of two numbers is 3,000

Where, 8% of one number is equal to 12% of another number.

Lets say the numbers are $x$ and $y$

Then,

$\implies \: x + y = 3000. \: . \: . \: . \bf(i)$

Now,

$\implies\: 8\% \: { \sf \: of} \: x = 12\% \: { \sf \: of} \: y$

$\implies\: \dfrac{8x}{100} = \dfrac{12y}{100}$

$\implies\: {8x}{} = {12y}{}$

$\implies\: {2x}= {3y}$

$\implies\: {x}= \dfrac{3y}{2}$

$\sf \: on \: substituting \: the \: value \: of \: \boldsymbol{x} \: in \: eq.(i) \: : -$

$\implies \: x + y = 3000$

$\implies \: \dfrac{3y}{2} + y = 3000$

$\implies \: \dfrac{3y + 2y}{2} = 3000$

$\implies \: {5y} = 3000 \times 2$

$\implies \: {5y} = 6000$

$\implies \: {y} = \dfrac{6000}{5}$

$\implies \: {y} = 1200$

Again, substitute the value of ‘y’ in eq.(i) :-

$\implies \: x + y = 3000$

$\implies \: x + 1200 = 3000$

$\implies \: x = 3000 - 1200$

$\implies \: x = 1800$

Hence, the numbers are 1,200 and 1,800