Question

the sum of two numbers is 3000. if 8% of one number is equal to 12% of the Other find the numbers

Answer 1

Let one number be x
Second number =3000 - x
According to the question
8x/100=(3000 - x) 12/100
8x/100 = (36000 - 12x)/100
20x =36000
x = 36000/20
x = 1800
Hence first number =1800
Second number =3000-1800 = 1200

Answer 2

$let \: the \: 1st \: number \: be \: x \\ then \: the \: 2nd \: number \: be \:(3000 - x) \\ by \: the \: question.... \\ = > \: x \times 8 \div 100 = (3000 - x) \times 12 \div 100 \\ = > 8x \div 100 = (36000 - 12x) \div 100 \\ = > 8x + 12x = 36000 \\ = > 20x = 36000 \\ = > x = 1800 \\ hence \: \\ \: 1st \: number \: = 1800 \\ 2nd \: number = 3000 - 1800 = 1200 \\ hope \: this \: will \: help \: you$